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Camillybulhosa1
@Camillybulhosa1
December 2019
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Determine o valor de x, sabendo que x= -b+ √ b² - 4ac)) /2a , quando a=1, b=5 e c=6
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Christopher007
X=-b±√b²-4a•c /2a
a=1; b=5; c=6
x=-5±√5²-4•1•6 /2•1
x=-5±√25-24 /2
x=-5±√1 /2
x=-5±1 /2
x'=-5+1 /2. x"=-5-1/2
x'=-4/2. x"=-6/2
x'=-2. x"=-3
3 votes
Thanks 6
Christopher007
Obrigado
sasa674
B²-4ac
5²-4.1.6
25-24
1
x=-5+-1/2.1
x¹=-5-1/2
x¹=-6/2
x¹=-3
x²=-5+1/2.1
x²=-4/2
x²=-2
1 votes
Thanks 0
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a=1; b=5; c=6
x=-5±√5²-4•1•6 /2•1
x=-5±√25-24 /2
x=-5±√1 /2
x=-5±1 /2
x'=-5+1 /2. x"=-5-1/2
x'=-4/2. x"=-6/2
x'=-2. x"=-3
5²-4.1.6
25-24
1
x=-5+-1/2.1
x¹=-5-1/2
x¹=-6/2
x¹=-3
x²=-5+1/2.1
x²=-4/2
x²=-2