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December 2019
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Dada a expressão x=-b+√b²-4.a.c/2.a sendo a=2, b=5 e c=-7, o valor numérico de x é?
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popeye1
Verified answer
A= 2, b= 5, c= -7
x= -b+√b²-4.a.c/2.a
x= (-5+√5²-4.2.(-7))/2.2
x= (-5+√25+56)/4
x= (-5√81)/4
x= (-5+9)/4
x= 4/4
x= 1
Forte abraço!
2 votes
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Verified answer
A= 2, b= 5, c= -7x= -b+√b²-4.a.c/2.a
x= (-5+√5²-4.2.(-7))/2.2
x= (-5+√25+56)/4
x= (-5√81)/4
x= (-5+9)/4
x= 4/4
x= 1
Forte abraço!