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Sarah95
@Sarah95
May 2020
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Determine as coordenadas do ponto medio do segmento cujas extremidades sao os pontos
a) A(1,2) e B(2,4)
b) C(3,5) e D(2,-3)
C)E(-1,-1/2) e F(-3,3/2)
d)G(-3,5) e H(3,-5)
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Temos então:
a.
A(1,2)
B(2,4)
Xm=x1+x2÷2
Xm=1+2÷2
Xm=3/2
Ym=y1+y2÷2
Ym=2+4÷2
Ym=6÷2
Ym=3
M(3/2,3)
b.
C(3,5)
D(2,-3)
Xm=x1+x2÷2
Xm=3+2÷2
Xm=5/2
Ym=y1+y2÷2
Ym=5+(-3)÷2
Ym=5-3÷2
Ym=2÷2
Ym=1
M(5/2,1)
c.
E(-1,-1/2)
F(-3,3/2)
Xm=x1+x2÷2
Xm=-1+(-3)÷2
Xm=-1-3÷2
Xm=-4÷2
Xm=-2
Ym=y1+y2÷2
Ym=-1/2+3/2÷2
Ym=2/2÷2
Ym=2/4
M(-2,2/4)
d.
G(-3,5)
H(3,-5)
Xm=x1+x2÷2
Xm=-3+3÷2
Xm=0
Ym=y1+y2÷2
Ym=5+(-5)÷2
Ym=5-5÷2
Ym=0
M(0,0)
5 votes
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W
Wandersson de Sousa Silva
Essse aplicativo é muito bom
0 votes
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Lista de comentários
a.
A(1,2)
B(2,4)
Xm=x1+x2÷2
Xm=1+2÷2
Xm=3/2
Ym=y1+y2÷2
Ym=2+4÷2
Ym=6÷2
Ym=3
M(3/2,3)
b.
C(3,5)
D(2,-3)
Xm=x1+x2÷2
Xm=3+2÷2
Xm=5/2
Ym=y1+y2÷2
Ym=5+(-3)÷2
Ym=5-3÷2
Ym=2÷2
Ym=1
M(5/2,1)
c.
E(-1,-1/2)
F(-3,3/2)
Xm=x1+x2÷2
Xm=-1+(-3)÷2
Xm=-1-3÷2
Xm=-4÷2
Xm=-2
Ym=y1+y2÷2
Ym=-1/2+3/2÷2
Ym=2/2÷2
Ym=2/4
M(-2,2/4)
d.
G(-3,5)
H(3,-5)
Xm=x1+x2÷2
Xm=-3+3÷2
Xm=0
Ym=y1+y2÷2
Ym=5+(-5)÷2
Ym=5-5÷2
Ym=0
M(0,0)