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Erica23
@Erica23
April 2020
1
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Sendo ( x' , y' ) e ( x'' , y '' ) as soluções do sistema { x² + 3xy =
0
{ x - y + 2
então y' + y'' e igual a ?
a) -5/2
b) -3/2
c) 3/2
d) 5/2
e) 3
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keisyykethellen
X² + 3xy = 0
x-y=2
-------
y=x-2
---------
x² + 3x(x-2) = 0
x² + 3x²-6x = 0
4x² - 6x = 0
x (4x-6)=0
4x-6=0
4x=6
x1=3/2
x2=0
(3/2)² + 3(3/2y) = 0 ~~~> 9/4 + 9/2y = 0
9/2y = -9/4
y1 = -0,5
y2=x2-2
y2=0-2
y2=-2
y1 + y2 = -0,5 + (-2) = -2,5 = -5/2
Alternativa "A"
10 votes
Thanks 17
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x-y=2
-------
y=x-2
---------
x² + 3x(x-2) = 0
x² + 3x²-6x = 0
4x² - 6x = 0
x (4x-6)=0
4x-6=0
4x=6
x1=3/2
x2=0
(3/2)² + 3(3/2y) = 0 ~~~> 9/4 + 9/2y = 0
9/2y = -9/4
y1 = -0,5
y2=x2-2
y2=0-2
y2=-2
y1 + y2 = -0,5 + (-2) = -2,5 = -5/2
Alternativa "A"