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MMchar
@MMchar
January 2020
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Simplifique :
cos(x+π/2)
sen(x-π/2)
sen(3π/2-x)
cos(3π/2+x)
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GeniusMaia
Cos(x+π/2) = cos(a)*cos(b) - sen(a)*sen(b)
= cosx*cos(π/2) - senx*sen(π/2)
= cosx*0 - senx*1
= -senx
sen(x-π/2) = sen(a)*cos(b) - sen(b)*cos(a)
= senx*cos(-
π/2) - sen(-π/2)*cosx
= senx*0 - (-1)*cosx
= cosx
sen(3π/2-x) = sen(3π/2)*cos(-x) - sen(-x)*cos(3π/2)
= -1*cosx -(-senx)*0
= -cosx
cos(3π/2+x) = cos(a)*cos(b) - sen(a)*sen(b)
= cos(3π/2)*cosx - sen(3π/2)*senx
= 0*cosx -(-1)*senx
= senx
Espero ter ajudado ;)
1 votes
Thanks 1
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= cosx*cos(π/2) - senx*sen(π/2)
= cosx*0 - senx*1
= -senx
sen(x-π/2) = sen(a)*cos(b) - sen(b)*cos(a)
= senx*cos(-π/2) - sen(-π/2)*cosx
= senx*0 - (-1)*cosx
= cosx
sen(3π/2-x) = sen(3π/2)*cos(-x) - sen(-x)*cos(3π/2)
= -1*cosx -(-senx)*0
= -cosx
cos(3π/2+x) = cos(a)*cos(b) - sen(a)*sen(b)
= cos(3π/2)*cosx - sen(3π/2)*senx
= 0*cosx -(-1)*senx
= senx
Espero ter ajudado ;)