Simplifique : cos(x+π/2) sen(x-π/2)sen(3π/2-x)cos(3π/2+x).... Pergunta de ideia deMMchar

January 2020 1 28 Report

Simplifique :

cos(x+π/2)
sen(x-π/2)
sen(3π/2-x)
cos(3π/2+x)

Lista de comentários

GeniusMaia Cos(x+π/2) = cos(a)*cos(b) - sen(a)*sen(b)
= cosx*cos(π/2) - senx*sen(π/2)
= cosx*0 - senx*1
= -senx

sen(x-π/2) = sen(a)*cos(b) - sen(b)*cos(a)
= senx*cos(-π/2) - sen(-π/2)*cosx
= senx*0 - (-1)*cosx
= cosx

sen(3π/2-x) = sen(3π/2)*cos(-x) - sen(-x)*cos(3π/2)
= -1*cosx -(-senx)*0
= -cosx

cos(3π/2+x) = cos(a)*cos(b) - sen(a)*sen(b)
= cos(3π/2)*cosx - sen(3π/2)*senx
= 0*cosx -(-1)*senx
= senx

Espero ter ajudado ;)

More Questions From This User See All

MMchar January 2020 | 0 Respostas

MMchar January 2020 | 0 Respostas

MMchar January 2020 | 0 Respostas

MMchar January 2020 | 0 Respostas

Helpful Links

Política de Privacidade

Termos e Condições

direito autoral

Helpful Social

Copyright © 2024 ELIBRARY.TIPS - All rights reserved.