20 PONTOS PRA QUEM RESPONDER!!!!!!!!!!!!!
Sendo x' e x'' as raízes da equação 6x²-x-1=0, o valor da expressão (x' + 1) (x'' + 1) é:
a) ( ) 1
b) ( ) 1/3
c) ( ) 2/3
d) ( ) -1
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