Resposta:
d) S = {4/3; 1}
Explicação passo a passo:
3x² - 7x + 4 = 0
a = 3 | b = -7 | c = 4
[tex]\frac{7 +/- \sqrt{(-7)^{2} - 4 . 3. 4} }{2.3} \\\\\frac{7 +/- \sqrt{49 - 4 . 3. 4} }{2.3} \\\\\\\frac{7 +/- \sqrt{49 - 4 . 12} }{2.3} \\\\\\\frac{7 +/- \sqrt{49 - 48} }{2.3} \\\\\\\frac{7 +/- \sqrt{1} }{2.3} \\\\\\\frac{7 +/- \sqrt{1} }{6} \\\\\\\frac{7 +/- 1}{6} \\\\\\x' = 7 + 1 / 6 = 8/6 = 4/3\\\\x" = 7 - 1 / 6 = 6/6 = 1[/tex]
S = {4/3; 1}
BONS ESTUDOS!!!!
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Resposta:
d) S = {4/3; 1}
Explicação passo a passo:
3x² - 7x + 4 = 0
a = 3 | b = -7 | c = 4
[tex]\frac{7 +/- \sqrt{(-7)^{2} - 4 . 3. 4} }{2.3} \\\\\frac{7 +/- \sqrt{49 - 4 . 3. 4} }{2.3} \\\\\\\frac{7 +/- \sqrt{49 - 4 . 12} }{2.3} \\\\\\\frac{7 +/- \sqrt{49 - 48} }{2.3} \\\\\\\frac{7 +/- \sqrt{1} }{2.3} \\\\\\\frac{7 +/- \sqrt{1} }{6} \\\\\\\frac{7 +/- 1}{6} \\\\\\x' = 7 + 1 / 6 = 8/6 = 4/3\\\\x" = 7 - 1 / 6 = 6/6 = 1[/tex]
S = {4/3; 1}
BONS ESTUDOS!!!!