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SubMat
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December 2019
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Considerando que log 3= 0,48 e log 2= 0,30, determine o valor de:
a) log 1,5
b) log 2/3
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fermat3
A)log 1.5 = log3/2=log3-log2= 0.48-0.30=0.18
b)log2/3=log2-log3=0.30-0.48=-0.18
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b)log2/3=log2-log3=0.30-0.48=-0.18