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FerrazCarol
@FerrazCarol
December 2019
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Simplifique a fracão algébrica
2ax+2ay+bx+by/3cx+3cy+dx+dy
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mozarth11
(2ax+2ay+bx+by) / (3cx+3cy+dx+dy) =
[2a*(x+y)+b*(x+y)] / [3c*(x+y)+d*(x+y)] =
[(2a+b)*(x+y)] / [(3c+d)*(x+y)] =
(2a+b) / (3c+d)
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[2a*(x+y)+b*(x+y)] / [3c*(x+y)+d*(x+y)] =
[(2a+b)*(x+y)] / [(3c+d)*(x+y)] =
(2a+b) / (3c+d)