X²-8x+q=0
Δ=0
Δ=b²-4ac
0=b²-4ac
b²-4ac=0
(-8)²-4.1.q=0
64-4q=0
-4q=-64
q=64/4
q=16
Gente ta certo aí?
Δ=0
Δ=b²-4ac
0=b²-4ac
b²-4ac=0
(-8)²-4.1.q=0
64-4q=0
-4q=-64
q=64/4
q=16
Gente ta certo aí?
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x^2-8x+q=0 onde q=16
Delta= b^2-4ac
Delta= (-8)^2-4.1.16
Delta= 64-64
Delta=0