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JoicyKelly2
@JoicyKelly2
December 2019
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Determine o zero da função de variáveis reais dada por: A) g (x)=x+6 B) h(x)=1/3x-9 C) f(x)=4x+12 D) k(x)=5x-25 E) t(x)= -4x+1/5 F) r(x)=x+2
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lsscherr
Lembrando, para achar a RAIZ de qualquer função, é necessário igualar o y = f(x) = 0.
Dessarte:
a) 0 = x + 6
x = -6
b) 0 = 1/3x -9
9 = 1/3x
27x = 1
x = 1/27
c) 0 = 4x+12
-12 = 4x
x = -3
d) 0 = 5x -25
25 = 5x
x = 5
e) 0 = -4x + 1/5
4x = 1/5
x = 1/20
f) 0 = x+2
x = -2
21 votes
Thanks 54
JoicyKelly2
Muito obrigada! Ajudou e muito!
lsscherr
=]
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Dessarte:
a) 0 = x + 6
x = -6
b) 0 = 1/3x -9
9 = 1/3x
27x = 1
x = 1/27
c) 0 = 4x+12
-12 = 4x
x = -3
d) 0 = 5x -25
25 = 5x
x = 5
e) 0 = -4x + 1/5
4x = 1/5
x = 1/20
f) 0 = x+2
x = -2