Se x(elevado a 5) = 100 e b(elevado a 3) = 100, então o logaritimo de x na base b vale:
a) -19/2
b) 3/5
c) 1
d) 2
c) NDA
a) -19/2
b) 3/5
c) 1
d) 2
c) NDA
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b^3 = 100
log x^5 = y
b^3
(x^5)^y = b^3
(100)^y = 100
y = 1
alternativa c.