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Nelly14
@Nelly14
May 2019
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Hey ! J'ai besoin de votre aide s'il vous plaît . En utilisant un tableau de signes, résoudre les inéquations suivantes :
i) -(3x+6)(10x+4)>0
j) (-2x+1)(15x+5)
------------------------>0
-4x+2/5
k) (x+1)(-4x+8)
--------------------->0
(-12x+3)(45x+5)
Merci pour votre aide ♡
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1/ - ( 3 x + 6) ( 10 x + 4 ) > 0
- 3 x - 6 = 0 ⇔ - 3 x = 6 ⇔ x = - 2
10 x + 4 = 0 ⇔ 10 x = - 4 ⇔ x = - 2/5
S ] - 2 : - 2/5 [
2/ [ ( - 2 x + 1) ( 15 x + 5) ] / - 4 x + 2/5 > 0
- 4 x + 2/5 = 0 ⇔ - 4 x = - 2/5 ⇔ x = 1/10 =
VI
- 2 x + 1 = 0 ⇔ - 2 x = - 1 ⇔ x = 1/2
15 x + 5 = 0 ⇔ 15 x = - 5 ⇔ x = - 5/15 = - 1/3
S ] -1/3 ; 1/10 [ ∪ ] 1/2 ; + ∞ [
3/ - 12 x + 3 = 0 ⇔ - 12 x = - 3 ⇔ x = 3/12 =
1/4 vi
45 x + 5 = 0 ⇔ 45 x = - 5 ⇔ x = - 5/45 =
- 1/9 vi
x + 1 = 0 ⇔ x = - 1
- 4 x + 8 = 0 ⇔ - 4 x = - 8 ⇔ x = 8/4 = 2
S ]- ∞ ; - 1/9[ ∪ ]- 1 : 1/4[ ∪ ]2 ; + ∞[
1 votes
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Hey ! Et merci d'avance pour votre aide ^^
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Verified answer
1/ - ( 3 x + 6) ( 10 x + 4 ) > 0- 3 x - 6 = 0 ⇔ - 3 x = 6 ⇔ x = - 2
10 x + 4 = 0 ⇔ 10 x = - 4 ⇔ x = - 2/5
S ] - 2 : - 2/5 [
2/ [ ( - 2 x + 1) ( 15 x + 5) ] / - 4 x + 2/5 > 0
- 4 x + 2/5 = 0 ⇔ - 4 x = - 2/5 ⇔ x = 1/10 = VI
- 2 x + 1 = 0 ⇔ - 2 x = - 1 ⇔ x = 1/2
15 x + 5 = 0 ⇔ 15 x = - 5 ⇔ x = - 5/15 = - 1/3
S ] -1/3 ; 1/10 [ ∪ ] 1/2 ; + ∞ [
3/ - 12 x + 3 = 0 ⇔ - 12 x = - 3 ⇔ x = 3/12 = 1/4 vi
45 x + 5 = 0 ⇔ 45 x = - 5 ⇔ x = - 5/45 = - 1/9 vi
x + 1 = 0 ⇔ x = - 1
- 4 x + 8 = 0 ⇔ - 4 x = - 8 ⇔ x = 8/4 = 2
S ]- ∞ ; - 1/9[ ∪ ]- 1 : 1/4[ ∪ ]2 ; + ∞[