Résoudre les inéquations suivantes : a) 3x +1> 0 b) -4x +7 < 4 c) 2x < x d) 8x +4 > 16x -4 Merci d'a.... Pergunta de ideia deNelly14

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bonjour^^
A/
$3x +1 \ \textgreater \ 0 \\ 3x \ \textgreater \ 0 - 1 \\ x\ \textgreater \ \frac{-1}{3} \\ S \left \{ {{X\ \textless \ \frac{-1}{3} }$
B/
$- 4x + 7 \ \textless \ 4 \\ -4x \ \textless \ 4-7 \\ -4x\ \textless \ -3 \\ x \ \textgreater \ \frac{-3}{-4} \\ x\ \textgreater \ \frac{3}{4}$
C/
$2x \ \textless \ x \\ 2x - x \ \textless \ 0 \\ x\ \textless \ 0$
D/
$8x +4 \ \textgreater \ 16x -4 \\ 8x - 16x \ \textgreater \ -4-4 \\ -8x\ \textgreater \ -8 \\ x\ \textless \ \frac{-8}{-8} \\ x\ \textless \ 1$

voilà ^^

1 votes Thanks 1

Stiaen Bonjour,

a) $3x+1\ \textgreater \ 0; \quad 3x\ \textgreater \ -1;\quad \boxed{x\ \textgreater \ -\dfrac{1}{3}}$

b) $-4x+7\ \textless \ 4;\quad -4x\ \textless \ 4-7;\quad -4x\ \textless \ -3;\quad\boxed{x\ \textgreater \ \dfrac{3}{4}}$

c) $2x\ \textless \ x;\quad2x-x\ \textless \ 0;\quad\boxed{x\ \textless \ 0}$

d)

$\quad 8x+4\ \textgreater \ 16x-4;\quad 8x-16x\ \textgreater \ -4-4;\quad-8x\ \textgreater \ -8;\quad\\\\ x\ \textgreater \ \dfrac{-8}{-8};\quad \boxed{x\ \textless \ 1}$

2 votes Thanks 1

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Hey ! Et merci d'avance pour votre aide ^^

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