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Estheeeeeeer
@Estheeeeeeer
September 2019
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Calcule as equações com os números complexos:
a)3i- (-5+7i) - (-i + 9)
b)(3-2i) (3-2i)
c)(7i+6) (7i+6)
d)8-3i/6+5i
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PedroVignerom
A) 3i-(-5+7i) -(-i+9) ( o sinal de negativo, indica o "-1" que está ali multiplicando )
3i+5-7i+i-9=0
-3i= 9-5
i= -4/3
b) (3-2i).(3-2i)=0
(3-2i)²=0
9+4i²=0
+4i²= -9
4i=-√9
4i= -3
i=-3/4
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3i+5-7i+i-9=0
-3i= 9-5
i= -4/3
b) (3-2i).(3-2i)=0
(3-2i)²=0
9+4i²=0
+4i²= -9
4i=-√9
4i= -3
i=-3/4