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SauloLima15
@SauloLima15
August 2019
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A soma dos 11 primeiros termos PG (1/2; 1/4; 1/8;...) É:
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tchubiladovaisp67ozg
SN={A1[(q^n)-1]}/q-1. Substituindo os termos temos: S11={0,5[(2^11)-1]}/2-1 ---> 0,5x2047=1023,5
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