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DanielR49
@DanielR49
May 2020
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A massa molecular do composto Na2 SO4 . 3H2O é igual :
Dados: H=1u O=16u P=31u
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JinhLurk
NaSO4 ou PO4? (S=32)
3 *18 = H2O
54
23 + 32 +
16*4
= 103 + 54 157 g/mol NaSO4.3H2O
48
23 + 31 + 16*4 = 102 + 54 156 g/mol NaPO4.3H2O
0 votes
Thanks 1
gleicybieber
Na=23x2=46 H= 1x2 = 2 Na2 SO4 . 3H2O=
S=32x1= 32 + O=1x16= 16 + 144.54=7,776g/mol
O=16x4= 64 18
144 g/mol 3H2O=3x18=54g/mol
0 votes
Thanks 2
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Lista de comentários
3 *18 = H2O 54
23 + 32 + 16*4 = 103 + 54 157 g/mol NaSO4.3H2O
48
23 + 31 + 16*4 = 102 + 54 156 g/mol NaPO4.3H2O
S=32x1= 32 + O=1x16= 16 + 144.54=7,776g/mol
O=16x4= 64 18
144 g/mol 3H2O=3x18=54g/mol