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Andressaqp8
@Andressaqp8
January 2020
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Alguém me ajuda com essa função ? Seja a função f (x), calcule f (1), f (-2), f (3,5)
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PauloBarros
F(x) = 4x - 3 , se x ≥ 0
f(x) = x² - 3x + 2 , se x < 0
***********************************
f(x) = 4x - 3 , se x ≥ 0
f(1) = 4.1 - 3
f(1) = 4 - 3
f(1) = 1
f(x) = x² - 3x + 2 , se x < 0
f(-2) = (-2)² - 3.(-2) + 2
f(-2) = 4 + 6 + 2
f(-2) = 12
f(x) = 4x - 3 , se x ≥ 0
f(3,5) = 4.3,5 - 3
f(3,5) = 14 - 3
f(3,5) = 11
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f(x) = x² - 3x + 2 , se x < 0
***********************************
f(x) = 4x - 3 , se x ≥ 0
f(1) = 4.1 - 3
f(1) = 4 - 3
f(1) = 1
f(x) = x² - 3x + 2 , se x < 0
f(-2) = (-2)² - 3.(-2) + 2
f(-2) = 4 + 6 + 2
f(-2) = 12
f(x) = 4x - 3 , se x ≥ 0
f(3,5) = 4.3,5 - 3
f(3,5) = 14 - 3
f(3,5) = 11