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Leonardopf1
@Leonardopf1
November 2019
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Alguém me ajuda por favor
Achar o valor de Y (função)
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fasimao
F(x) = x²+x-6. As imagens são:
f(-4) = (-4)²+(-4)-6 = 16-4-6 = 6
f(-3) =(-3)²+(-3)-6 = 9 -3 -6 = 0
f(0) = (0)²+(0)-6 = 0 + 0 - 6 = -6
f(1) = (1)²+(1)-6 = 1 + 1 -6 = -4
f(2) = (2)²+(2)-6 = 4 +2 -6 = 0
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Leonardopf1
sabe como se faz o Gráfico?
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Lista de comentários
f(-4) = (-4)²+(-4)-6 = 16-4-6 = 6
f(-3) =(-3)²+(-3)-6 = 9 -3 -6 = 0
f(0) = (0)²+(0)-6 = 0 + 0 - 6 = -6
f(1) = (1)²+(1)-6 = 1 + 1 -6 = -4
f(2) = (2)²+(2)-6 = 4 +2 -6 = 0