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December 2019
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Alguém pode me ajudar com as medidas desses ângulos? Por favoor!!
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Andrecs1
I) ângulos opostos pelo vértice (o.p.v.)
x + 100° = 160° - 3x
x + 3x = 160° - 100°
4x = 60°
x = 60°/4
x = 15°
ii) ângulos suplementares
(6x + 15°) + (2x + 5°) = 180°
6x + 2x + 15° + 5° = 180°
8x + 20° = 180°
8x = 180° - 20°
8x = 160°
x = 160°/8
x = 20°
Espero ter ajudado!!! Bons estudos!!!
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KaylaneMartins
Muito obrigada!!
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x + 100° = 160° - 3x
x + 3x = 160° - 100°
4x = 60°
x = 60°/4
x = 15°
ii) ângulos suplementares
(6x + 15°) + (2x + 5°) = 180°
6x + 2x + 15° + 5° = 180°
8x + 20° = 180°
8x = 180° - 20°
8x = 160°
x = 160°/8
x = 20°
Espero ter ajudado!!! Bons estudos!!!