Juros composto:
Dados:
C → 20000
t → 4 anos → 4·12 = 48 meses
i → 0,5%a.m → 0,5/100 → 0,005%a.m
J → ?
M → ?
____________________________
M=C·(i+1)^t
M=20000·(1+0,005)^48
M=20000·(1,005)^48
M=20000·1,27 (aproximado)
M≅R$25.400
Juros simples:
J=c·i·t
J=20000·0,005·48
J=100·48
J=R$4.800
_______________
M=C+J
M=20000+4800
M=R$24.800
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Lista de comentários
M=C(1+i)^n
i=0,5/100=0,005
n=4 anos=48 meses
M=20.000(1+0,005)^48
M=20.000(1,005)^48
M=25.409,78
Resposta: R$25.409,78
Boa noite!
Juros composto:
Dados:
C → 20000
t → 4 anos → 4·12 = 48 meses
i → 0,5%a.m → 0,5/100 → 0,005%a.m
J → ?
M → ?
____________________________
M=C·(i+1)^t
M=20000·(1+0,005)^48
M=20000·(1,005)^48
M=20000·1,27 (aproximado)
M≅R$25.400
____________________________
Juros simples:
J=c·i·t
J=20000·0,005·48
J=100·48
J=R$4.800
_______________
M=C+J
M=20000+4800
M=R$24.800
____________________________
Att;Guilherme Lima