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Catiasnd
@Catiasnd
November 2019
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Aplicando R$ 2.100,00 durante 3meses, João recebeu R$ 163,80 de juros. Qual foi a taxa mensal dessa aplicação?
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Indalecio
I/j*100/C/t
i=163,80*100/2100/3
i=16380/2100/3
i=7,8/3
i=2,6
Resposta: Taxa de 2,6%a.m.
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doidoazul
Se for juros composto será:
2100+163,80= 2100*(1+i*100)^3
1,065814 = (1+i*100)^3
(1+i*100) =1,0216
i= 2,16%
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Lista de comentários
i=163,80*100/2100/3
i=16380/2100/3
i=7,8/3
i=2,6
Resposta: Taxa de 2,6%a.m.
2100+163,80= 2100*(1+i*100)^3
1,065814 = (1+i*100)^3
(1+i*100) =1,0216
i= 2,16%