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Bolacha1111
@Bolacha1111
October 2019
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Boa noite! Se alguém souber me ensinar PASSO A PASSO agradeço. Gabarito é D
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lazinhojose
Mmc=(x+1)(x-1)
(x-2)(x-1)+3=(x+1)+x
x²-x-2x+2+3=2x+1
x²-3x+5-1-2x=0
x²-5x+4=0
Por Bhaskara:
x=1
x'=4
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(x-2)(x-1)+3=(x+1)+x
x²-x-2x+2+3=2x+1
x²-3x+5-1-2x=0
x²-5x+4=0
Por Bhaskara:
x=1
x'=4