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Quentin11399
@Quentin11399
May 2019
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Bonjour a tous j'ai besoin d'aide pour cette exercice c'est pour demain merci d'avance
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ProfdeMaths1
Verified answer
(DA,DC)=π/2 rad
(AC,AD)=π/6 rad
(DC,AC)=(CD,CA)=π/3 rad
(BA,DC)=-π rad
(AC,BC)=(CA,CB)=π/3 rad
(AD,CB)=-5π/6 rad
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Verified answer
(DA,DC)=π/2 rad(AC,AD)=π/6 rad
(DC,AC)=(CD,CA)=π/3 rad
(BA,DC)=-π rad
(AC,BC)=(CA,CB)=π/3 rad
(AD,CB)=-5π/6 rad