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Curiiosity
@Curiiosity
May 2019
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Bonjour, quelqu’un pourrait-il m’expliquer comme faire cet exercice ?
Je crois que c’est une suite récurrente mais je ne comprends pas comment on calcule les termes.
Merci d’avance
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guestnosdevoir
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Bonsoir,
Ex3.7.
U1=(U0+1)=-2(U0)+10=-2(-1)+10=12
U3=(U2+1)=-2(U2)+10=-2(-2(U1)+10)+10=4(U1)-20+10=4(U1)-10=4(12)-10=48-10=38.
:)
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Bonsoir,Ex3.7.
U1=(U0+1)=-2(U0)+10=-2(-1)+10=12
U3=(U2+1)=-2(U2)+10=-2(-2(U1)+10)+10=4(U1)-20+10=4(U1)-10=4(12)-10=48-10=38.
:)