Bonjour,
600+x²-50x=500
<=> x² -50x + 100=0
calculons le discriminant :
=b²-4ac
=2500-400
= 2100>0
donc l'équation admet deux solutions :
x1 = (-b-√Δ)/2a = 25-5√21
x2 = (-b+√Δ)/2a = 25+5√21
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Bonjour,
600+x²-50x=500
<=> x² -50x + 100=0
calculons le discriminant :
=b²-4ac
=2500-400
= 2100>0
donc l'équation admet deux solutions :
x1 = (-b-√Δ)/2a = 25-5√21
x2 = (-b+√Δ)/2a = 25+5√21