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JonatasVargas
@JonatasVargas
December 2019
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Calcular a derivada da função,
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paulomathematikus
Y=x/(x+1)
Seja f(x)=x e g(x)=x+1.Temos que:
dy/dx=(f'*g-g'*f)/g²
dy/dx=(1*x+1-1*x)/(x+1)² ⇒ dy/dx=(x+1-x)/(x+1)² ⇒ dy/dx=1/(x+1)²
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Seja f(x)=x e g(x)=x+1.Temos que:
dy/dx=(f'*g-g'*f)/g²
dy/dx=(1*x+1-1*x)/(x+1)² ⇒ dy/dx=(x+1-x)/(x+1)² ⇒ dy/dx=1/(x+1)²