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Leet111
@Leet111
December 2019
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Calcule a porcentagem em massa do elemento indicado em cada um dos seguintes compostos:
a)carbono em C2H2
b)hidrogênio em (NH4)2SO4
c)carbono em C18H24O2
d)carbono em C18H27NO3
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MP39
Olá!!!
a) M(C2H2) = 2•12+2•1 = 26g/mol
M(2C) = 2 • 12 = 24g/mol
26g ----------- 100%
24g ---------- X
X = 92,30%
b) NH4)2SO4
M( NH4)2SO4) = 2•14+8•1+32+4•16 = 132g/mol
132g --------------- 100%
8g ------------------- H
H = 6,06%
c) M( C18H24O2) = 18•12+24•1+2•16 = 272g/mol
272g ---------- 100%
216g ------------ C
C = 79,41%
d) M( C18H27NO3) = 18•12+27•1+14+3•16 = 275g/mol
275g ---------- 100%
216g ------------ C
C = 78,54%
2 votes
Thanks 3
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Lista de comentários
a) M(C2H2) = 2•12+2•1 = 26g/mol
M(2C) = 2 • 12 = 24g/mol
26g ----------- 100%
24g ---------- X
X = 92,30%
b) NH4)2SO4
M( NH4)2SO4) = 2•14+8•1+32+4•16 = 132g/mol
132g --------------- 100%
8g ------------------- H
H = 6,06%
c) M( C18H24O2) = 18•12+24•1+2•16 = 272g/mol
272g ---------- 100%
216g ------------ C
C = 79,41%
d) M( C18H27NO3) = 18•12+27•1+14+3•16 = 275g/mol
275g ---------- 100%
216g ------------ C
C = 78,54%