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Hard123
@Hard123
December 2019
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Calcule a soma dos 7 primeiros termos da PG (3^0, 3^4, 3^2, 3^3,...)
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Jovi77
3 - y)² + y² = 29
9 - 6y + y² + y² = 29
2y² - 6y + 9 - 29 = 0
2y² - 6y - 20 = 0 (simplifica por 2)
y² - 3y - 10 = 0
(y + 2)*(y - 5) = 0
y + 2 = 0
y' = -2
y - 5 = 0
y'' = 5
x - 2 = 3
x = 3 + 2
x' = 5
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Lista de comentários
9 - 6y + y² + y² = 29
2y² - 6y + 9 - 29 = 0
2y² - 6y - 20 = 0 (simplifica por 2)
y² - 3y - 10 = 0
(y + 2)*(y - 5) = 0
y + 2 = 0
y' = -2
y - 5 = 0
y'' = 5
x - 2 = 3
x = 3 + 2
x' = 5