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Viih20011970
@Viih20011970
January 2020
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Calcule a soma dos oito primeiros elementos da Pá (3,15,27,...)
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Primeiramente, vamos calcular o 8° termo.
a₁ = 3
a₂ = 15
n = 8
r = 15 - 3 = 12
a₈ = a₁ + (n - 1) . r
a₈ = 3 + (8 - 1) . 12
a₈ = 3 + 7 . 12
a₈ = 3 + 84
a₈ = 87
Soma dos termos:
S₈ = [(a₁ + a₈) . n] / 2
S₈ = [(3 + 87) . 12] / 2
S₈ = [90 . 12] / 2
S₈ = 1080 / 2
S₈ =
540
Espero ter ajudado. Feliz Natal!
1 votes
Thanks 1
Viih20011970
Obgda. .pra vc tbm
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a₁ = 3
a₂ = 15
n = 8
r = 15 - 3 = 12
a₈ = a₁ + (n - 1) . r
a₈ = 3 + (8 - 1) . 12
a₈ = 3 + 7 . 12
a₈ = 3 + 84
a₈ = 87
Soma dos termos:
S₈ = [(a₁ + a₈) . n] / 2
S₈ = [(3 + 87) . 12] / 2
S₈ = [90 . 12] / 2
S₈ = 1080 / 2
S₈ = 540
Espero ter ajudado. Feliz Natal!