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JoelNeto123
@JoelNeto123
January 2020
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Calcule com aproximação de décimos por falta ou por excesso
a) √2
b)√3
c)√5
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eversonboy
√2
2 ////
1,41...
-1 24 . 4 = 96
100 281 . 1 = 281
-96
400
281
119
√3
3 //////
1,7 ...
-1 27 . 7 = 189
200
189
11
√5
5 ////
2,2 ...
4 42 . 2 = 84
100
-84
16
2 votes
Thanks 4
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2 //// 1,41...
-1 24 . 4 = 96
100 281 . 1 = 281
-96
400
281
119
√3
3 ////// 1,7 ...
-1 27 . 7 = 189
200
189
11
√5
5 //// 2,2 ...
4 42 . 2 = 84
100
-84
16