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AlexA286
@AlexA286
December 2019
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Calcule f(x) = x³ + 1
a) f( 0 )
b) f( 1 )
c) f (√2)
d) f ( - 1 )
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albertrieben
Calcule f(x) = x³ + 1
a) f( 0 ) = 1b) f( 1 ) = 1 + 1 = 2c) f (√2) = 2√2 + 1 d) f ( - 1 ) = -1 + 1 = 0
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a) f( 0 ) = 1b) f( 1 ) = 1 + 1 = 2c) f (√2) = 2√2 + 1 d) f ( - 1 ) = -1 + 1 = 0