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CaioAguiar69
@CaioAguiar69
January 2020
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Calcule o perímetro dos triângulos, cujos vértices são dados abaixo: a) A (-2,5), B (4,-3) e C (-2,-6)
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gabriel17fluzao
A (-2,5)
B (4,-3)
C (-2,-6)
dAB=√(xB-xA)²+(YB-YA)²
dAB= √(4-(-2))²+(-3-5)²
dAB=√36+64
dAB=√100
dAB=10
dAC=√(XC-XA)²+(YC-YA)²
dAC=√(-2-(-2))²+(-6-5)²
dAC=√0+121
dAC=11
dBC=√(XC-XB)²+(YC-YB)²
dBC=√(-2-4)²+(-6-(-3))²
dBC=√36+9
dBC=√45
dBC=3√5
PERIMETRO
2p= 10+11+3√5
2p=21+3√5
2p=3(7+√5)
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Lista de comentários
B (4,-3)
C (-2,-6)
dAB=√(xB-xA)²+(YB-YA)²
dAB= √(4-(-2))²+(-3-5)²
dAB=√36+64
dAB=√100
dAB=10
dAC=√(XC-XA)²+(YC-YA)²
dAC=√(-2-(-2))²+(-6-5)²
dAC=√0+121
dAC=11
dBC=√(XC-XB)²+(YC-YB)²
dBC=√(-2-4)²+(-6-(-3))²
dBC=√36+9
dBC=√45
dBC=3√5
PERIMETRO
2p= 10+11+3√5
2p=21+3√5
2p=3(7+√5)