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ANNESSANTOS1
@ANNESSANTOS1
August 2019
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Calcule o vértice da seguinte função.
a)-x²-2x+3
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araujofranca
As coordenadas do vértice (x, y) = (-b/2a, -delta/4a)
Função: - x² - 2x + 3 a = - 1 b = - 2 c = 3
x (vértice) = - b/2a = - (- 2) / 2(-1) = 2 / -2 = - 1
y (vértice) = - delta/4a = f( x(vértice) )
= f(-1) = - (-1)² - 2.(-1) + 3
= - (+1) + 2 + 3
= - 1 + 5 = 4
Resposta: V(x, y) = V(- 1, 4)
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Lista de comentários
As coordenadas do vértice (x, y) = (-b/2a, -delta/4a)
Função: - x² - 2x + 3 a = - 1 b = - 2 c = 3
x (vértice) = - b/2a = - (- 2) / 2(-1) = 2 / -2 = - 1
y (vértice) = - delta/4a = f( x(vértice) )
= f(-1) = - (-1)² - 2.(-1) + 3
= - (+1) + 2 + 3
= - 1 + 5 = 4
Resposta: V(x, y) = V(- 1, 4)