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@Onurbs
November 2019
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Calcule os valores de A e de B a fim de que a igualdade a seguir seja verdadeira:
x^4 - 3x^3 + 4x^2 = (x^2 -5) (x^2 -3x + 9) + (ax + b)
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x^4 - 3x^3 + 4x^2 = (x^2 -5) (x^2 -3x + 9) + (ax + b)
x²*(x²-3x+4)
= (x^2 -5) (x^2 -3x + 9) + (ax + b)
x²*(x²-3x) +x²*4=x²*(x²-3x) + x²*9 -5*(x²-3x+9) + (ax+b)
x²*4=x²*9 -5*(x²-3x+9) + (ax+b)
0=x²*5 -5*(x²-3x+9) + (ax+b)
0= 5*x²-5x²+15x-45+ax+b
0= 15x-45+ax+b
-15x+45=ax+b
a=-15
b=45
2 votes
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x²*(x²-3x+4)= (x^2 -5) (x^2 -3x + 9) + (ax + b)
x²*(x²-3x) +x²*4=x²*(x²-3x) + x²*9 -5*(x²-3x+9) + (ax+b)
x²*4=x²*9 -5*(x²-3x+9) + (ax+b)
0=x²*5 -5*(x²-3x+9) + (ax+b)
0= 5*x²-5x²+15x-45+ax+b
0= 15x-45+ax+b
-15x+45=ax+b
a=-15
b=45