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RayssaBrito
@RayssaBrito
December 2019
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Calcule usando a fórmula de Bhaskara x^2-8x+12=0
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rocka9104
Fórmula de Bhaskara x=-b±√∆/2a
x²-8x+12=0
a=1
b=-8
c=12
∆=b²-4ac
∆=(-8)²-4*1*12
∆=64-48
∆=16
X=-(-8)±√16/2
x=8±4/2
x1=8-4/2
x1=2
x2=8+4/2
x2=6
S={2,6}
1 votes
Thanks 1
jjzejunio
X²-8x+12=0
a= 1, b= -8, c= 12
delta= b²-4.a.c
delta= (-8)²-4.1.12
delta= 64-48
delta= 16
x= -b±√delta/2.a
x= 8±√16/2.1
x= 8±4/2
x= 8+4/2= 12/2= 6
x= 8-4/2= 4/2= 2
s={ 6,2 }
0 votes
Thanks 1
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Lista de comentários
x²-8x+12=0
a=1
b=-8
c=12
∆=b²-4ac
∆=(-8)²-4*1*12
∆=64-48
∆=16
X=-(-8)±√16/2
x=8±4/2
x1=8-4/2
x1=2
x2=8+4/2
x2=6
S={2,6}
a= 1, b= -8, c= 12
delta= b²-4.a.c
delta= (-8)²-4.1.12
delta= 64-48
delta= 16
x= -b±√delta/2.a
x= 8±√16/2.1
x= 8±4/2
x= 8+4/2= 12/2= 6
x= 8-4/2= 4/2= 2
s={ 6,2 }