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Jscaetano53
@Jscaetano53
May 2020
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Como encontrar as coordenadas de um vetor?
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debora20
V.(2i -j +k) = 6 ------------> v (a, b, c)
v.(2i -j +k) = 6
(a, b, c)*( 2, -1, 1) = 2a - b + c = 6...........(I)
(2, 3, -1)*(a, b, c) = 2a + 3b -c = 0 ..........(II)
(1, -2, 3)*(a, b, c) = a -2b + 3c = 0...........(II)
Resolva o sistema
2a - b + c = 6
2a + 3b -c = 0
a -2b + 3c = 0
e verás que a = 3 , b = -3 e c = -3, logo
V(3, -3, -3)
Espero ajudar ´
1 votes
Thanks 3
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Lista de comentários
v.(2i -j +k) = 6
(a, b, c)*( 2, -1, 1) = 2a - b + c = 6...........(I)
(2, 3, -1)*(a, b, c) = 2a + 3b -c = 0 ..........(II)
(1, -2, 3)*(a, b, c) = a -2b + 3c = 0...........(II)
Resolva o sistema
2a - b + c = 6
2a + 3b -c = 0
a -2b + 3c = 0
e verás que a = 3 , b = -3 e c = -3, logo
V(3, -3, -3)
Espero ajudar ´