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IngridSSilva1
@IngridSSilva1
January 2020
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Como faço para resolver o polinômio (x³-y³).(x+y)-(x²+y²).x²-y²) na forma mais simples possível?
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GabrielMagal1
(x³-y³).(x+y) - (x²+y²).(x²-y²) = (x-y)(x²+xy+y²).(x+y) - (x²+y²).(x²-y²)
(x³-y³).(x+y) - (x²+y²).(x²-y²) = (x-y).(x+y).(x²+xy+y²) - (x²+y²).(x²-y²)
(x³-y³).(x+y) - (x²+y²).(x²-y²) = (x²-y²).(x²+xy+y²) - (x²+y²).(x²-y²)
(x³-y³).(x+y) - (x²+y²).(x²-y²) = (x²-y²).[x²+xy+y² - (x²+y²)]
(x³-y³).(x+y) - (x²+y²).(x²-y²) = (x²-y²).[x²+xy+y² - x²-y²]
(x³-y³).(x+y) - (x²+y²).(x²-y²) = (x²-y²).xy
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(x³-y³).(x+y) - (x²+y²).(x²-y²) = (x-y).(x+y).(x²+xy+y²) - (x²+y²).(x²-y²)
(x³-y³).(x+y) - (x²+y²).(x²-y²) = (x²-y²).(x²+xy+y²) - (x²+y²).(x²-y²)
(x³-y³).(x+y) - (x²+y²).(x²-y²) = (x²-y²).[x²+xy+y² - (x²+y²)]
(x³-y³).(x+y) - (x²+y²).(x²-y²) = (x²-y²).[x²+xy+y² - x²-y²]
(x³-y³).(x+y) - (x²+y²).(x²-y²) = (x²-y²).xy