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Leticiacastroc
@Leticiacastroc
May 2020
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Como resolver essas equaçoes do 2°grau?
2x²-7=7(x-7)
x²+x=0
-3y²+15y=0
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ChrisMont
X²+X=0
Δ=3
X1=-1-1,7 ÷2
X1=- 1,35
X2=-1+1,7 ÷ 2
X2=0,35
0 votes
Thanks 0
48wallace
2x²-7=7x-49
2x²-7x-42=0
Δ=(-7)²-4.2.(-42)
Δ=385 não possui raiz quadrada exata
b)
x(x+1)=0
x'=0
x+1=0
x"=-1
c)
jogando logo no discriminante
Δ=15²-4.(-3).0
Δ=225
x'=-15+15/-6
x'=0
x"=-15-15/-6
x"=5
0 votes
Thanks 0
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Lista de comentários
Δ=3
X1=-1-1,7 ÷2
X1=- 1,35
X2=-1+1,7 ÷ 2
X2=0,35
2x²-7x-42=0
Δ=(-7)²-4.2.(-42)
Δ=385 não possui raiz quadrada exata
b)
x(x+1)=0
x'=0
x+1=0
x"=-1
c)
jogando logo no discriminante
Δ=15²-4.(-3).0
Δ=225
x'=-15+15/-6
x'=0
x"=-15-15/-6
x"=5