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Carolina17
@Carolina17
April 2020
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Como resolver?
a) X²+X.(2X-45)=0
b)3x.(x+2)+(x-1)²=x+1
obg! :)
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nayrasindel
X²+x.(2x-45)=0
x²+2x²-45x=0
3x²-45x=0
a) 3 b) -45 c) 0
Delta= -b²-4.a.c
Delta= -(-45²)-4.3.0
Delta= 2025
x=-b=- a raiz² de delta sobre 2.a
x ´= - b+ (raiz² de delta)2025/2.3
x ´= 45+45/6
x ´= 0;
x ´´ = -b- (raiz²) 2025/2.3
x ´´= 45-45/6
x ´´ = 96/ 6
x ´´ = -15
Ah amiga só consegui essa, boa sorte ! rsrs
2 votes
Thanks 6
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x²+2x²-45x=0
3x²-45x=0
a) 3 b) -45 c) 0
Delta= -b²-4.a.c
Delta= -(-45²)-4.3.0
Delta= 2025
x=-b=- a raiz² de delta sobre 2.a
x ´= - b+ (raiz² de delta)2025/2.3
x ´= 45+45/6
x ´= 0;
x ´´ = -b- (raiz²) 2025/2.3
x ´´= 45-45/6
x ´´ = 96/ 6
x ´´ = -15
Ah amiga só consegui essa, boa sorte ! rsrs