Articles
Register
Sign In
Search
ThataVitoria
@ThataVitoria
May 2019
1
54
Report
Considerando A= x+1 e B= x-1, determine o mmc de x^3 + x^2 - x+1 em função de A e B.
Please enter comments
Please enter your name.
Please enter the correct email address.
Agree to
terms and service
You must agree before submitting.
Send
Lista de comentários
anaalice1742
A = x + 1
b = x - 1
p = x³ + x² - x - 1
q = x³ - x² - x + 1
Determinar o mdc(p, q) e mmc(p, q) em função de a e b.
Solução:
Fatorando p e q temos:
p = (x - 1).(x + 1)² = a²b
q = (x + 1).(x - 1)² = ab²
Portanto:
mdc(p, q) = mdc(a²b, ab²) = ab
mmc(p, q) = pq / mdc(p, q) = a³b³ / ab = a²b²
Resposta:
mdc(x³ + x² - x - 1, x³ - x² - x + 1) = ab
mmc(x³ + x² - x - 1, x³ - x² - x + 1) = a²b
1 votes
Thanks 1
More Questions From This User
See All
ThataVitoria
December 2019 | 0 Respostas
Responda
ThataVitoria
November 2019 | 0 Respostas
Responda
ThataVitoria
November 2019 | 0 Respostas
Responda
ThataVitoria
November 2019 | 0 Respostas
Responda
ThataVitoria
November 2019 | 0 Respostas
Responda
ThataVitoria
November 2019 | 0 Respostas
Responda
ThataVitoria
November 2019 | 0 Respostas
Responda
ThataVitoria
November 2019 | 0 Respostas
Responda
ThataVitoria
November 2019 | 0 Respostas
Responda
ThataVitoria
October 2019 | 0 Respostas
Responda
Recomendar perguntas
Deividyfreitas
May 2020 | 0 Respostas
BlackShot
May 2020 | 0 Respostas
Vanessakellen
May 2020 | 0 Respostas
Guiduarter
May 2020 | 0 Respostas
Mrzaine
May 2020 | 0 Respostas
O QUE SERIA AUTONOMIA?
Grazifer
May 2020 | 0 Respostas
Joazinho
May 2020 | 0 Respostas
a palavra rapidez formou se de qual derivacao
Celiana
May 2020 | 0 Respostas
Joazinho
May 2020 | 0 Respostas
Anatercia
May 2020 | 0 Respostas
×
Report "Considerando A= x+1 e B= x-1, determine o mmc de x^3 + x^2 - x+1 em função de A e B.... Pergunta de ideia de ThataVitoria"
Your name
Email
Reason
-Select Reason-
Pornographic
Defamatory
Illegal/Unlawful
Spam
Other Terms Of Service Violation
File a copyright complaint
Description
Helpful Links
Sobre nós
Política de Privacidade
Termos e Condições
direito autoral
Contate-Nos
Helpful Social
Get monthly updates
Submit
Copyright © 2024 ELIBRARY.TIPS - All rights reserved.
Lista de comentários
b = x - 1
p = x³ + x² - x - 1
q = x³ - x² - x + 1
Determinar o mdc(p, q) e mmc(p, q) em função de a e b.
Solução:
Fatorando p e q temos:
p = (x - 1).(x + 1)² = a²b
q = (x + 1).(x - 1)² = ab²
Portanto:
mdc(p, q) = mdc(a²b, ab²) = ab
mmc(p, q) = pq / mdc(p, q) = a³b³ / ab = a²b²
Resposta:
mdc(x³ + x² - x - 1, x³ - x² - x + 1) = ab
mmc(x³ + x² - x - 1, x³ - x² - x + 1) = a²b