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ThataVitoria
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May 2019
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Considerando A= x+1 e B= x-1, determine o mmc de x^3 + x^2 - x+1 em função de A e B.
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anaalice1742
A = x + 1
b = x - 1
p = x³ + x² - x - 1
q = x³ - x² - x + 1
Determinar o mdc(p, q) e mmc(p, q) em função de a e b.
Solução:
Fatorando p e q temos:
p = (x - 1).(x + 1)² = a²b
q = (x + 1).(x - 1)² = ab²
Portanto:
mdc(p, q) = mdc(a²b, ab²) = ab
mmc(p, q) = pq / mdc(p, q) = a³b³ / ab = a²b²
Resposta:
mdc(x³ + x² - x - 1, x³ - x² - x + 1) = ab
mmc(x³ + x² - x - 1, x³ - x² - x + 1) = a²b
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Lista de comentários
b = x - 1
p = x³ + x² - x - 1
q = x³ - x² - x + 1
Determinar o mdc(p, q) e mmc(p, q) em função de a e b.
Solução:
Fatorando p e q temos:
p = (x - 1).(x + 1)² = a²b
q = (x + 1).(x - 1)² = ab²
Portanto:
mdc(p, q) = mdc(a²b, ab²) = ab
mmc(p, q) = pq / mdc(p, q) = a³b³ / ab = a²b²
Resposta:
mdc(x³ + x² - x - 1, x³ - x² - x + 1) = ab
mmc(x³ + x² - x - 1, x³ - x² - x + 1) = a²b