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GuilhermeMarques22
@GuilhermeMarques22
December 2019
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Considerando que p(x)= 2x^3 -kx^2 + 3x - 2k para que valores de k temos p(2)= 4?
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vhp1996
Basta vc substituir x por 2:
p(2)=2.2³-k.2²+3.2-2k
4=2.8-4k+6-2k
4=16+6-6k
-6k = 4-22
-6k=-18
k=-18/-6=3
4 votes
Thanks 7
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Lista de comentários
p(2)=2.2³-k.2²+3.2-2k
4=2.8-4k+6-2k
4=16+6-6k
-6k = 4-22
-6k=-18
k=-18/-6=3