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Frnaciele
@Frnaciele
December 2019
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Dada a função f (x) = 1
-------
x - 2
Determine:
c) f (√3 + 3)
d) f (5 - √2)
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rodrigoreichert
Vamos considerar a função f(x) = 1 / (x - 2).
c)
f(√3 - 3) = 1 / ((√3 - 3) - 2)
f(√3 - 3) = 1 / (√3 - 5)
f(√3 - 3) = (1 * (√3 + 5)) / ((√3 - 5) * (√3 + 5))
f(√3 - 3) = (√3 + 5) / (3 + 5√3 - 5√3 - 25)
f(√3 - 3) = (√3 + 5) / (-22)
f(√3 - 3) = -(√3 + 5) / 22
d)
f(5 - √2) = 1 / ((5 - √2) - 2)
f(5 - √2) = 1 / (3 - √2)
f(5 - √2) = (1 * (3 + √2)) / ((3 - √2) * (3 + √2))
f(5 - √2) = (3 + √2) / (9 + 3√2 - 3√2 - 2)
f(5 - √2) = (3 + √2) / 7
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c)
f(√3 - 3) = 1 / ((√3 - 3) - 2)
f(√3 - 3) = 1 / (√3 - 5)
f(√3 - 3) = (1 * (√3 + 5)) / ((√3 - 5) * (√3 + 5))
f(√3 - 3) = (√3 + 5) / (3 + 5√3 - 5√3 - 25)
f(√3 - 3) = (√3 + 5) / (-22)
f(√3 - 3) = -(√3 + 5) / 22
d)
f(5 - √2) = 1 / ((5 - √2) - 2)
f(5 - √2) = 1 / (3 - √2)
f(5 - √2) = (1 * (3 + √2)) / ((3 - √2) * (3 + √2))
f(5 - √2) = (3 + √2) / (9 + 3√2 - 3√2 - 2)
f(5 - √2) = (3 + √2) / 7