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GiovannaOliveira02
@GiovannaOliveira02
December 2019
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Dada a função f (x) = 2x elevado a 2 +5 , determine o valor de : a) f (0) b)f (x)=7
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NightsFalling
f(x)=2x²+5
a)x=0 f(x)=?
f(0)=2.(0)²+5
f(0)=5
b)x=? f(x)=7
f(x)=2x²+5
7=2x²+5
7-5=2x²
2=2x²
(invertendo a função de lado)
2x²=2
x²=2/2
x²=1
x=(+/-)√1
x=(+/-)1
(☞゚ヮ゚)☞ ☜(゚ヮ゚☜)
1 votes
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Lista de comentários
f(x)=2x²+5
a)x=0 f(x)=?
f(0)=2.(0)²+5
f(0)=5
b)x=? f(x)=7
f(x)=2x²+5
7=2x²+5
7-5=2x²
2=2x²
(invertendo a função de lado)
2x²=2
x²=2/2
x²=1
x=(+/-)√1
x=(+/-)1
(☞゚ヮ゚)☞ ☜(゚ヮ゚☜)