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LuhCG1
@LuhCG1
December 2019
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Dada a função Y = -x² + 6x Determine:
a) Os Zeros Da Função:
b) O Valor Maximo De Y:
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Verified answer
Y= -x^2+6x
a)
▲=6^2-4(-1)(0)
▲=36+0
▲=36
x'=(-6+V36)÷2(-1)
x'=0
x"=(-6-V36)÷2(-1)
x"=6
S={0,6}
b)
Yv= -▲/4a
Yv= -36/4(-1)
Yv= 9
Xv= -b/2a
Xv= -6/2(-1)
Xv= 3
S={3,9}
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Verified answer
Y= -x^2+6xa)
▲=6^2-4(-1)(0)
▲=36+0
▲=36
x'=(-6+V36)÷2(-1)
x'=0
x"=(-6-V36)÷2(-1)
x"=6
S={0,6}
b)
Yv= -▲/4a
Yv= -36/4(-1)
Yv= 9
Xv= -b/2a
Xv= -6/2(-1)
Xv= 3
S={3,9}