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Shazant7
@Shazant7
January 2020
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Dada a matriz A = (aij)4×4 em que aij = i + j , sei < , i j sei > j , determine a soma dos elementos a 23+ a 34.
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guimaciel07
Verified answer
A23 = 2+3 = 5
a34 = 3+4 = 7
a23+a34 = 5 + 7 = 12
1 votes
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Shazant7
valeu!
guimaciel07
de boa
albertrieben
Bom dia Shazant
A23 = i + j = 2 + 3 = 5
A34 = i + j = 3 + 4 = 7
A23 + A34 = 5 + 7 = 12
.
1 votes
Thanks 5
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Verified answer
A23 = 2+3 = 5a34 = 3+4 = 7
a23+a34 = 5 + 7 = 12
A23 = i + j = 2 + 3 = 5
A34 = i + j = 3 + 4 = 7
A23 + A34 = 5 + 7 = 12
.