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AnonymousCTV
@AnonymousCTV
November 2019
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Dadas as retas r e s paralelas distintas, quantos triângulos também distintos podemos construir, escolhendo 9 pontos de r e 15 pontos de s?
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albertrieben
Boa tarde
N = C(9,2) * C(15,1) + C(15,2) * C(9,1)
N = 9!/2!7! * 15!/1!14! + 15!/2!13! * 9!1!8!
N = 36 * 15 + 7*15 * 9
N = 540 + 945 = 1485
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N = C(9,2) * C(15,1) + C(15,2) * C(9,1)
N = 9!/2!7! * 15!/1!14! + 15!/2!13! * 9!1!8!
N = 36 * 15 + 7*15 * 9
N = 540 + 945 = 1485