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Nathyydias
@Nathyydias
January 2020
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Dados cos26°=0,90 calcule :
a) sen 26° .
b)tg 26°
c)sen 64°
d)cos 64°
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zhiek
A)sen² +cos²=1
sen² +0,9² =1 ..sen²=1-0,81= 0,19 sen² =0,19 ...sen=0,43
b)tg26° =0,43/0,9 =0,48
c) sen(64)=sen(90-26)= sen90°.cos26 -sen26°.cos90
1.0,9 - 0,43.0 =0,9
d)cos(64) =cos(90-26) =cos90.cos26 +sen90.sen26
0.0,9 + 1.0,43 =0,43
espero ter ajudado
(╯°□°）╯
2 votes
Thanks 1
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Lista de comentários
sen² +0,9² =1 ..sen²=1-0,81= 0,19 sen² =0,19 ...sen=0,43
b)tg26° =0,43/0,9 =0,48
c) sen(64)=sen(90-26)= sen90°.cos26 -sen26°.cos90
1.0,9 - 0,43.0 =0,9
d)cos(64) =cos(90-26) =cos90.cos26 +sen90.sen26
0.0,9 + 1.0,43 =0,43
espero ter ajudado (╯°□°）╯