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Sila51
@Sila51
April 2019
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Dans chaque cas,trouver le PGCD des deux nombres
a)14 et 12 ;
b)1 et 29;
c)20 et 40;
d)10 et 15;
e)27 et 18;
f)54 et 54;
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Juulien
Verified answer
A) 4
b) 1
c) 20
d) 5
e) 9
f)54
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MrEagle
J'utilise la méthode de la division euclidienne.
a) 14 = 12 x 1 + 2
12 = 2 x 6 + 0
PGCD ( 14 ; 12 ) = 2
b)
Le PGCD est 1 bien sur.
c) 40 = 20 x 2 + 0
PGCD ( 40 ; 20 ) = 20
d) 15 = 10 x 1 + 5
10 = 5 x 2 + 0
PGCD ( 15 ; 10 ) = 5
e) 27 = 18 x 1 + 9
18 = 9 x 2 + 0
PGCD ( 27 ; 18 ) = 9
f) 54 = 54 x 1 + 0
PGCD ( 54 ; 54 ) = 54
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Verified answer
A) 4b) 1
c) 20
d) 5
e) 9
f)54
a) 14 = 12 x 1 + 2
12 = 2 x 6 + 0
PGCD ( 14 ; 12 ) = 2
b) Le PGCD est 1 bien sur.
c) 40 = 20 x 2 + 0
PGCD ( 40 ; 20 ) = 20
d) 15 = 10 x 1 + 5
10 = 5 x 2 + 0
PGCD ( 15 ; 10 ) = 5
e) 27 = 18 x 1 + 9
18 = 9 x 2 + 0
PGCD ( 27 ; 18 ) = 9
f) 54 = 54 x 1 + 0
PGCD ( 54 ; 54 ) = 54