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November 2019
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Data a pa (1,4). A soma dos 40 primeiro termos dessa pa vale? Ajuda
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DOCA10
Sn = (a1 + an) x n / 2
a1 = 4
an = ?
n = 40
r = 4 - 1 = 3
Sn = ?
an = a1 + (n - 1) r
an = 1 + (40 - 1) 3
an = 1 + 117
an = 118
Logo:
Sn = (1 + 118) 40 / 2
Sn = (119 x 40) / 2
Sn = 4760 / 2
Sn = 2380
;-)
0 votes
Thanks 1
albertrieben
Boa tarde
PA
a1 = 1
a2 = 4
razão
r = a2 - a1
r = 4 - 1 = 3
termo geral
an = a1 + r*(n - 1)
a40 = a1 + 39r
a40 = 1 + 39*3
a40 = 118
soma
Sn = (a1 + an)*n/2
S40 = (1 + 118)*40/2
S40 = 119*20
S40 = 2380
0 votes
Thanks 1
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Lista de comentários
a1 = 4
an = ?
n = 40
r = 4 - 1 = 3
Sn = ?
an = a1 + (n - 1) r
an = 1 + (40 - 1) 3
an = 1 + 117
an = 118
Logo:
Sn = (1 + 118) 40 / 2
Sn = (119 x 40) / 2
Sn = 4760 / 2
Sn = 2380
;-)
PA
a1 = 1
a2 = 4
razão
r = a2 - a1
r = 4 - 1 = 3
termo geral
an = a1 + r*(n - 1)
a40 = a1 + 39r
a40 = 1 + 39*3
a40 = 118
soma
Sn = (a1 + an)*n/2
S40 = (1 + 118)*40/2
S40 = 119*20
S40 = 2380